匹配字符串中特定格式的字符串， 在一串字符串中，先找到特殊规则的substring, 然后再提取相关的位置value
strings = ['result-2023-08-18-6g1s1ch-DB9909',
'result-2023-08-18-4g1s3ch-DB9909',
'result-2023-08-18-1g4s1ch-DB9909',
'result-2023-08-18-1g1s1ch-DB9909']
pattern = r'(\d+)([Gg])(\d+)([Ss])(\d+)([Cc][Hh])'
results = []
for s in strings:
match = re.search(pattern, s)
if match:
print(match.group())
g = match.group(2) #匹配第2个括号的内容
s = match.group(4) #匹配第4个括号的内容
ch = match.group(6) #匹配第6个括号的内容
string = match.group(1) + g + match.group(3) + s + match.group(5) + ch
results.append(string)
print(results)
db_pattern = r'([Dd][Bb])(\d+)'
match = re.search(db_pattern, strings[0])
if match:
print(match.group())
db = match.group(1) #匹配第2个括号的内容
number = match.group(2) #匹配第4个括号的内容
db_number = db + number输出内容
6g1s1ch
4g1s3ch
1g4s1ch
1g1s1ch
['6g1s1ch', '4g1s3ch', '1g4s1ch', '1g1s1ch']
DB9909
fullDump_pDevice00000286923A19B0_frame000_1g1s1ch.gfxbench_inst2_F535
pDevice后面可能是一串其他数字和字母，只需要截取从frame001开始的字符串，如：
frame000_1g1s1ch.gfxbench_inst2_F535
import re s = "fullDump_pDevice00000286923A19B0_frame000_1g1s1ch.gfxbench_inst2_F535" # Match the prefix to remove prefix_pattern = r'^fullDump_pDevice\d+_' # Use sub() to remove the matched prefix result = re.sub(prefix_pattern, '', s) print(result)
上述正则表达式并不能准确替换掉，输出结果还是原来的字符串：
fullDump_pDevice00000286923A19B0_frame000_1g1s1ch.gfxbench_inst2_F535
后使用如下表达式：
s = "fullDump_pDevice0000028fd3B19D0_frame000_1g1s1ch.gfxbench_inst2_F535" prefix_pattern = r'^fullDump_pDevice(\d+)([A-Za-z0-9]+)_' new = re.sub(prefix_pattern, "", s) print(new)
输出结果：
frame000_1g1s1ch.gfxbench_inst2_F535
以上为个人经验，希望能给大家一个参考，也希望大家多多支持本站。